LeetCode Weekly Contest 146 2問目 - Shortest Path with Alternating Colors [1129]

Source

LeetCode Weekly Contest 146
問題文

問題概要

省略

解法

省略

cLayversion 20190721-1)のコード [C++に変換後]

#include<bits/stdc++.h>
using namespace std;
void *wmem;
template<class S, class T> inline S min_L(S a,T b){
  return a<=b?a:b;
}
struct graph{
  int N, **edge, *es;
  void setEdge(int N__, int M, int A[], int B[], void **mem = &wmem){
    int i;
    N = N__;
    es = (int*)(*mem);
    edge = (int**)(es+N);
    edge[0] = (int*)(edge+N);
    for(i=0;i<N;i++){
      es[i] = 0;
    }
    for(i=0;i<M;i++){
      es[A[i]]++;
      es[B[i]]++;
    }
    for(i=1;i<N;i++){
      edge[i] = edge[i-1] + es[i-1];
    }
    (*mem) = edge[N-1] + es[N-1];
    for(i=0;i<N;i++){
      es[i] = 0;
    }
    for(i=0;i<M;i++){
      edge[A[i]][es[A[i]]++] = B[i];
      edge[B[i]][es[B[i]]++] = A[i];
    }
  }
  void setDirectEdge(int N__, int M, int A[], int B[], void **mem = &wmem){
    int i;
    N = N__;
    es = (int*)(*mem);
    edge = (int**)(es+N);
    edge[0] = (int*)(edge+N);
    for(i=0;i<N;i++){
      es[i] = 0;
    }
    for(i=0;i<M;i++){
      es[A[i]]++;
    }
    for(i=1;i<N;i++){
      edge[i] = edge[i-1] + es[i-1];
    }
    (*mem) = edge[N-1] + es[N-1];
    for(i=0;i<N;i++){
      es[i] = 0;
    }
    for(i=0;i<M;i++){
      edge[A[i]][es[A[i]]++] = B[i];
    }
  }
  graph reverse(void **mem = &wmem){
    graph g;
    int i, j, k;
    g.N = N;
    g.es = (int*)(*mem);
    g.edge = (int**)(g.es + N);
    g.edge[0] = (int*)(g.edge + N);
    for(i=0;i<N;i++){
      g.es[i] = 0;
    }
    for(i=0;i<N;i++){
      for(j=0;j<es[i];j++){
        g.es[edge[i][j]]++;
      }
    }
    for(i=1;i<N;i++){
      g.edge[i] = g.edge[i-1] + g.es[i-1];
    }
    *mem = g.edge[N-1] + g.es[N-1];
    for(i=0;i<N;i++){
      g.es[i] = 0;
    }
    for(i=0;i<N;i++){
      for(j=0;j<es[i];j++){
        k = edge[i][j];
        g.edge[k][g.es[k]++] = i;
      }
    }
    return g;
  }
  graph reduce(int tn, int ind[], int self_e = 0, int dep_e = 0, void **mem = &wmem){
    graph g;
    int M=0, i, j, k, x, y;
    pair<int,int> *A;
    for(i=0;i<N;i++){
      M += es[i];
    }
    A = (pair<int,int>*)((int*)((int**)(*mem) + tn) + tn + M);
    M = 0;
    for(i=0;i<N;i++){
      x = ind[i];
      if(x < 0){
        continue;
      }
      for(j=0;j<es[i];j++){
        y = ind[edge[i][j]];
        if(y < 0){
          continue;
        }
        if(self_e==0 && x==y){
          continue;
        }
        A[M++] = make_pair(x, y);
      }
    }
    if(dep_e==0){
      sort(A, A+M);
      k = 0;
      for(i=0;i<M;i++){
        if(k && A[k-1]==A[i]){
          continue;
        }
        A[k++] = A[i];
      }
      M = k;
    }
    g.N = tn;
    g.es = (int*)(*mem);
    g.edge = (int**)(g.es + tn);
    g.edge[0] = (int*)(g.edge + tn);
    for(i=0;i<tn;i++){
      g.es[i] = 0;
    }
    for(i=0;i<M;i++){
      g.es[A[i].first]++;
    }
    for(i=1;i<tn;i++){
      g.edge[i] = g.edge[i-1] + g.es[i-1];
    }
    *mem = g.edge[tn-1] + g.es[tn-1];
    for(i=0;i<tn;i++){
      g.es[i] = 0;
    }
    for(i=0;i<M;i++){
      j = A[i].first;
      k = A[i].second;
      g.edge[j][g.es[j]++] = k;
    }
    return g;
  }
  void getDist(int root, int res[], void *mem = wmem){
    int i, j, k, *q, s, z;
    q=(int*)mem;
    for(i=0;i<N;i++){
      res[i]=-1;
    }
    res[root]=0;
    s=0;
    z=1;
    q[0]=root;
    while(z){
      i=q[s++];
      z--;
      for(j=0;j<es[i];j++){
        k=edge[i][j];
        if(res[k]>=0){
          continue;
        }
        res[k]=res[i]+1;
        q[s+z++]=k;
      }
    }
  }
  inline int sccDFS(int num[], int st, int mx){
    int i, j;
    num[st]=-2;
    for(i=0;i<es[st];i++){
      j=edge[st][i];
      if(num[j]==-1){
        mx=sccDFS(num,j,mx);
      }
    }
    num[st]=mx;
    return mx+1;
  }
  int scc(int res[], void *mem = wmem){
    graph r;
    int i, j, k, *nrv, *num, ret=0, *st, st_size;
    r = reverse(&mem);
    st = (int*)mem;
    num = st+N;
    nrv = num + N;
    for(i=0;i<N;i++){
      res[i] = num[i] = -1;
    }
    k = 0;
    for(i=0;i<N;i++){
      if(num[i]==-1){
        k = sccDFS(num,i,k);
      }
    }
    for(i=0;i<N;i++){
      nrv[num[i]] = i;
    }
    for(k=N-1;k>=0;k--){
      i=nrv[k];
      if(res[i]>=0){
        continue;
      }
      res[i]=ret;
      st_size=0;
      st[st_size++]=i;
      while(st_size){
        i=st[--st_size];
        for(j=0;j<r.es[i];j++){
          if(res[r.edge[i][j]]==-1){
            res[r.edge[i][j]]=ret;
            st[st_size++]=r.edge[i][j];
          }
        }
      }
      ret++;
    }
    return ret;
  }
  inline void bccDFS(int v, int u, int *res, int *rt, int &rts, int *S, int &Ss, int *inS, int *num, int &tm){
    int i, k;
    num[v] = ++tm;
    S[Ss++] = v;
    inS[v] = 1;
    rt[rts++] = v;
    for(i=0;i<es[v];i++){
      int w=edge[v][i];
      if(!num[w]){
        bccDFS(w, v, res, rt, rts, S, Ss, inS, num, tm);
      }
      else if(u != w && inS[w]){
        while(num[rt[rts-1]] > num[w]){
          rts--;
        }
      }
    }
    if(v == rt[rts-1]){
      k = S[Ss-1];
      for(;;){
        int w=S[--Ss];
        inS[w] = 0;
        res[w] = k;
        if(v==w){
          break;
        }
      }
      rts--;
    }
  }
  int bcc(int res[], void *mem=wmem){
    int *S, Ss=0, i, *inS, k, *num, *rt, rts=0, tm=0;
    pair<int,int> *arr;
    num = (int*)mem;
    rt = num + N;
    S = rt + N;
    inS = S + N;
    memset(num, 0, sizeof(int)*N);
    memset(inS, 0, sizeof(int)*N);
    for(i=0;i<N;i++){
      if(!num[i]){
        bccDFS(i, N, res, rt, rts, S, Ss, inS, num, tm);
      }
    }
    arr = (pair<int,int>*)mem;
    for(i=0;i<N;i++){
      arr[i].first = res[i];
      arr[i].second = i;
    }
    sort(arr, arr+N);
    k = 0;
    for(i=0;i<N;i++){
      if(i && arr[i].first != arr[i-1].first){
        k++;
      }
      res[arr[i].second] = k;
    }
    return k+1;
  }
  int shortestPath(const int s, const int t, int res[], void *mem=wmem){
    int *b, i, j, k, *q, qe=0, qs=0;
    b = (int*)mem;
    q = b + N;
    for(i=0;i<N;i++){
      b[i] = -1;
    }
    b[s] = -2;
    q[qe++] = s;
    while(qe > qs){
      i = q[qs++];
      for(j=0;j<es[i];j++){
        k = edge[i][j];
        if(b[k]!=-1){
          continue;
        }
        b[k] = i;
        q[qe++] = k;
      }
      if(b[t]!=-1){
        break;
      }
    }
    if(b[t]==-1){
      return -1;
    }
    k = 0;
    res[k] = i = t;
    while(i != s){
      res[++k] = (i = b[i]);
    }
    std::reverse(res, res+k+1);
    return k;
  }
}
;
char memarr[96000000];
int M;
int A[1000];
int B[1000];
int dist1[1000];
int dist2[1000];
int main2(){
  wmem = memarr;
  return 0;
}
class Solution{
  public:
  vector<int> shortestAlternatingPaths(int n, vector<vector<int>>& RR, vector<vector<int>>& BB){
    main2();
    graph g;
    int i;
    vector<int> res;
    void *mem=wmem;
    M = 0;
    for(i=0;i<RR.size();i++){
      A[M] = RR[i][0];
      B[M++] = RR[i][1] + n;
    }
    for(i=0;i<BB.size();i++){
      A[M] = BB[i][0] + n;
      B[M++] = BB[i][1];
    }
    g.setDirectEdge(2*n, M, A, B);
    g.getDist(0, dist1);
    g.getDist(n, dist2);
    for(i=0;i<2*n;i++){
      if(dist1[i]==-1){
        dist1[i] = 1073709056;
      }
    }
    for(i=0;i<2*n;i++){
      if(dist2[i]==-1){
        dist2[i] = 1073709056;
      }
    }
    for(i=0;i<n;i++){
      res.push_back(min_L(min_L(min_L(dist1[i], dist1[i+n]), dist2[i]), dist2[i+n]));
    }
    for(i=0;i<n;i++){
      if(res[i]==1073709056){
        res[i] = -1;
      }
    }
    wmem = mem;
    return res;
  }
}
;
// cLay varsion 20190721-1

// --- original code ---
// int M, A[1000], B[1000], dist1[1000], dist2[1000];
// 
// class Solution {
// public:
//   vector<int> shortestAlternatingPaths(int n, vector<vector<int>>& RR, vector<vector<int>>& BB) {
//     int i;
//     graph g;
//     void *mem = wmem;
//     vector<int> res;
// 
//     M = 0;
//     rep(i,RR.size()){
//       A[M] = RR[i][0];
//       B[M++] = RR[i][1] + n;
//     }
//     rep(i,BB.size()){
//       A[M] = BB[i][0] + n;
//       B[M++] = BB[i][1];
//     }
// 
//     g.setDirectEdge(2n, M, A, B);
//     g.getDist(0, dist1);
//     g.getDist(n, dist2);
// 
//     rep(i,2n) if(dist1[i]==-1) dist1[i] = int_inf;
//     rep(i,2n) if(dist2[i]==-1) dist2[i] = int_inf;
//     rep(i,n) res.push_back( min(dist1[i],dist1[i+n],dist2[i],dist2[i+n]) );
//     rep(i,n) if(res[i]==int_inf) res[i] = -1;
// 
//     wmem = mem;
//     return res;
//   }
// };
// 
// {
//   // main関数を適当に処理する
// }

Current time: 2024年04月26日22時58分48秒
Last modified: 2019年07月22日08時00分52秒 (by laycrs)
Tags: Competitive_Programming_Incomplete LeetCode
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